6x-4x^2-2=0

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Solution for 6x-4x^2-2=0 equation: 



6x-4x^2-2=0

a = -4; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·(-4)·(-2)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*-4}=\frac{-8}{-8}
=1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*-4}=\frac{-4}{-8}
=1/2
$

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